|
Academic Open Internet Journal |
Volume 11, 2004 |
By
Senior Lecturer
Email: mukam_fotsing_j_a@fulbrightweb.org
And
Graduate Student
University of Yaounde I
Ecole Normale Supérieure
P. O. Box 3482
Yaounde
CAMEROON
The measurement of the thermal conductivity of Sapelli is carried
out. A comparison of the experimental
and theoretical results is made from some calculation models available in the
literature. Equations predicting
the thermal conductivity according to
the moisture content are proposed in the longitudinal, radial, and tangential
directions.
Keywords: Sapelli, thermal
conductivity, moisture content.
Thermal conductivity is one of the physical properties of wood essential
to drying. Within the framework of this
paper, we will study it using a local wood of Cameroon: Sapelli
(Entrandrophragma cylindricum). Wood is
a heterogeneous and porous material.
The phenomena of heat transfer in wood depends on the geometry of the
wood, as well as porosity. Thermal
conductivity is different in solids, gases and liquids. As wood is a heterogeneous medium containing
the three phases, its thermal conductivity is only an apparent conductivity
because it results from complex exchanges concerning simultaneously: conduction in gases, conduction in the
liquids, conduction in the solid (constitutive matter). Wood cannot be considered completely dried,
so we can classify it among the mediums with three phases: a solid phase of
thermal conductivity ls occupying a fraction of volume (1 - e); a
gas phase (air in our case) occupying the voluminal fraction qa = e - q1 and of thermal conductivity lg; a liquid phase occupying the
voluminal fraction q1 and of thermal conductivity ll.
The experimental principle lies in the determination of the quantity of
heat which is transferred through a sample in steady operation. The material we want to measure the
conductivity is placed between an isothermal capacity and a box (of parallelepipedic
form) surrounded by a framework (figure 1).
By imposing on the faces of the sample the temperatures T1 and T2 with
T1 > T2, the one-way flow Q crossing surface S of the sample thickness e is
given by:
(1)
It comes
(2)
Figure 1: Longitudinal section of the device used for the experiments.

Heat exchange between the box and outside is never null. It is thus difficult to obtain in a uniform
way a temperature Ti inside the box equal to that of outside Te. There is thus a loss Qo such as:
Qt = Qo + Q (3)
With
Qo = K(Te – Ti) (4)
Where K is a factor dependent on the box (in W.°K-1).
The experimental study was undertaken on Sapelli which is a very
abundant wood in the cameroonian forest.
This study uses a technique of steady operation and emphasizes the
influence on the thermal conductivity of the planes of cuts in wood and the
moisture content. We will propose a linear model of conductivity according to
moisture according to the three plans of wood.
The experimental device is made up:
- of an isothermal enclosure A
of dimension 181 cm X 76 cm x26 cm. A
system of cooling of environment: it
consists of a heat exchanger supplied with a temperature regulator of
fluid.
- of one (or two) box (es) B made of plywood isolated from the
interior. One places the wood sample to
be tested in this box equipped with a transmitter of heat C.
- temperature gauges on the two faces of the sample
- of a transformer which feeds heating resistance in tension
- of a multimeter which is used to measure the voltage at the boundaries
of E like its impedance.
Once the sample is inserted in the box trough the open face, a tension V
is applied at the boundary of the transmitter C. Then a liquid flows in the system and a gradient of temperature
is produced in the sample. Temperatures
TC and TF are
produced on the hot and cold faces. At the stabilisation of these temperatures
the steady state is reached, and we can write the following equations:
-
the Joule effect
produced by the heater C:
(5)
-
thermal losses
through box B:
(6)
-
conductive flow
through the sample
(7)
Where
E is the thickness of the sample (m)
S normal surface with the heat flow (m2)
TC the temperature of its face higher (hot)
TF the temperature of its cold face
V the terminal voltage of the transmitter of heat (v)
C1 the total loss coefficient through the box
R the resistance of transmitter
TA the ambient temperature of the room
TB the ambient temperature of the interior of the box.
Then the energy balance is given by:
(8)
what leads finally to:
(9)
In this last equation, some data are measured at the beginning of
handling. They are:
the thickness and the sample surface (length multiplied by
width). Resistance R is measured after
handling. As for the total loss
coefficient of the box, it is fixed at 0,16 W.°K-1.
TA, TB, TC,
TF and V. At the beginning
of each handling, the sample is weighed and at the end, one obtains a mass Mo
which does not vary practically any more.
One deduces from the masses initial and finale moisture for each
handling.
L and l are respectively the
length and the width of the sample.
Equivalent conductivity is given by equation (9) with
S = l x L (10)
After the weighing of a 27x27x3 cm sample, we introduced it into a
climatic chamber with the temperatures TC and TF ranging
between 15°C and 25°C. At the end of a
series of measurements, the sample is placed for 48 hours in a drying oven at
105°C in order to obtain the value of the real dry mass. The water content is calculated thereafter
and the results are recorded in the tables below.
Table 1: Thermal conductivity in
the axial direction according to
Moisture content
|
H (%) |
16,7 |
21,3 |
27,3 |
36,7 |
42 |
52,7 |
60,7 |
68,7 |
|
l
(W.m-1.°K-1) |
0,375 |
0,4 |
0,438 |
0,475 |
0,463 |
0,513 |
0,55 |
0,54 |
H (%): Water content of wood
l (W.m-1.°K-1): Conductivity
thermal
Table 2: Thermal conductivity in
the tangential direction according
to moisture content
|
H (%) |
3,3 |
8 |
14 |
22 |
25,3 |
29,3 |
34 |
37,3 |
50 |
55,3 |
66,7 |
|
l
(W.m-1.°K-1) |
0,16 |
0,17 |
0,18 |
0,20 |
0,21 |
0,22 |
0,23 |
0,24 |
0,26 |
0,29 |
0,31 |
Table 3: Thermal conductivity in
the radial direction according to moisture content
|
H (%) |
3,3 |
10 |
12,7 |
20,7 |
24,7 |
32 |
36,7 |
47,3 |
51,3 |
61,3 |
65,3 |
|
l
(W.m-1.°K-1) |
0,16 |
0,19 |
0,19 |
0,21 |
0,23 |
0,24 |
0,25 |
0,29 |
0,31 |
0,31 |
0,32 |
According to the graphs, we note that l = uH +
v where u is the slope of the right-hand side and v the ordinate for a null
moisture content in each case. Thermal
conductivity thus varies practically in a linear way with moisture content in
the material used (Sapelli). We note
that this thermal conductivity decreases with moisture content. This remains in conformity with the theory.
During drying, water is replaced by gaz, and we know that thermal conductivity
of water is higher than that of gas. A
meticulous observation leads us to note that the plan of cut has an influence
on conductivity, this is explained by the difference between the three
equations of right-hand side. By
extrapolating the line obtained to the dry state, we have:
(11)
This result is close to that obtained by Maclean (5).
Figure
3: Thermal conductivity as a function
of moisture content (axial).
Figure 4 :
Thermal conductivity as a function of moisture content (tangential).
Figure
5 : Thermal conductivity as a function of moisture content (radial).
We expose here a
model of calculation if the space of the pores is saturated by a thermal gas of
conductivity lg and the
conductivity of the solid being ls. The model consists in
calculating the limits of the values of the thermal conductivity of wood in a
dry state. It is shown that apparent thermal conductivity,
for a porosity e of porous and
heterogeneous mediums, always lies between conductivities of two mediums (gas
/solid) made of parallel layers.
Series model (lower Limit): the mediums consist of solid layers and
gases perpendicular to the heat flow.
Figure 6: Perpendicular disposition of the phases solid and gas with the heat flow.
In this case
(12)
The porous environment consists of layers of solid and gases parallel
with the heat flow.

Figure 7: Disposition in the direction parallel with the heat flow of the solid and gas phases.
We have
(13)
Application of the models series and parallel to wood
In wood, the solid phase is the substance of the cellular wall (lignin)
and the gas phase is the air. The wood
saturated with the air is wood in a dry state.
For the calculation of lmax and lmin, we will use the
tabular values (given by Siau) of lg = 0,024 W.°K-1.m-1, ls = 0,44 W.°K-1.m-1, ls/ / =0,88 W.°K-1.m-1 and the physical characteristics (e= eg) of the sample of Sapelli given by NGOHE-EKAM (2). Then, it will be checked if lmax < L <lmin (experimental values).
e:
Porosity of the air
lf : thermal conductivity of the
fluid
ls: thermal conductivity of the
solid phase.
We know that:
(14)
and
M = rV (15)
But
(16)
then
(17)
The resolution gives :
(18)
it comes
(19)
The density rm of the lignin given by NGOHE-EKAM (2) is 1,5x 103kg.m-3.
Dry porosity is
(20)
The porosity in a saturated state is
(21)
Table 4: Physical characteristics of Sapelli
|
Sapelli |
M0
(g) |
r0 |
rh |
ea |
el |
|
axial |
1234 |
601 |
1189 |
0,6 |
0,62 |
|
radial |
1164 |
610 |